1+x^2 d x= - Vidyadip

MCQ

$\int \sqrt{1+x^2} d x=$

✓
$\frac{x}{2} \sqrt{1+x^2}+\frac{1}{2} \log \left(x+\sqrt{1+x^2}\right)+c$
B
$\frac{2}{3}\left(1+x^2\right)^{3 / 2}+c$
C
$\frac{1}{3}\left(1+x^2\right)+c$
D
$\frac{(x)}{\sqrt{1+x^2}}+c$

✓

Answer

Correct option: A.

$\frac{x}{2} \sqrt{1+x^2}+\frac{1}{2} \log \left(x+\sqrt{1+x^2}\right)+c$

(a) $\frac{x}{2} \sqrt{1+x^2}+\frac{1}{2} \log \left(x+\sqrt{1+x^2}\right)+c$

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