MCQ
$\int_{}^{} {{{\tan }^{ - 1}}x\,dx = } $
- A$x{\tan ^{ - 1}}x + \frac{1}{2}\log (1 + {x^2})$
- ✓$x{\tan ^{ - 1}}x - \frac{1}{2}\log (1 + {x^2})$
- C$(x - 1){\tan ^{ - 1}}x$
- D$x{\tan ^{ - 1}}x - \log (1 + {x^2})$
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