( ^ -1 x ) d x= - Vidyadip

MCQ

$\int \tan \left(\sin ^{-1} x\right) \cdot d x=$

A
$\left(1-x^2\right)^{-\frac{1}{2}}+c$
B
$\left(1-x^2\right)^{\frac{1}{2}}+c$
C
$\frac{\tan ^m X }{\sqrt{1-x^2}}+c$
✓
$-\sqrt{1-x^2}+c$

✓

Answer

Correct option: D.

$-\sqrt{1-x^2}+c$

$-\sqrt{1-x^2}+c$ Hint: $\sin ^{-1} x=\tan ^{-1}\left(\frac{x}{\sqrt{1-x^2}}\right)$

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