MCQ
$\int_{}^{} {u\frac{{{d^2}v}}{{d{x^2}}}dx - \int_{}^{} {v\frac{{{d^2}u}}{{d{x^2}}}dx = } } $
- ✓$u\frac{{dv}}{{dx}} - v\frac{{du}}{{dx}} + c$
- B$2\frac{{du}}{{dx}}\frac{{dv}}{{dx}} + c$
- C$uv + c$
- D$c$
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