MCQ
$\int_{}^{} {{x^n}\log x\;dx = } $
  • A
    $\frac{{{x^{n + 1}}}}{{n + 1}}\left\{ {\log x + \frac{1}{{n + 1}}} \right\} + c$
  • B
    $\frac{{{x^{n + 1}}}}{{n + 1}}\left\{ {\log x + \frac{2}{{n + 1}}} \right\} + c$
  • C
    $\frac{{{x^{n + 1}}}}{{n + 1}}\left\{ {2\log x - \frac{1}{{n + 1}}} \right\} + c$
  • $\frac{{{x^{n + 1}}}}{{n + 1}}\left\{ {\log x - \frac{1}{{n + 1}}} \right\} + c$

Answer

Correct option: D.
$\frac{{{x^{n + 1}}}}{{n + 1}}\left\{ {\log x - \frac{1}{{n + 1}}} \right\} + c$
d
(d)$\int_{}^{} {{x^n}\log x\,dx} = \log x\,.\,\frac{{{x^{n + 1}}}}{{n + 1}} - \int_{}^{} {\frac{{{x^{n + 1}}}}{{n + 1}}\,.\,\frac{1}{x}\,dx} $
$ = \frac{{{x^{n + 1}}}}{{n + 1}}\log x - \frac{{{x^{n + 1}}}}{{{{(n + 1)}^2}}} + c = \frac{{{x^{n + 1}}}}{{n + 1}}\left[ {\log x - \frac{1}{{n + 1}}} \right] + c.$

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