MCQ
$\int_0^{\frac{\pi}{2}} \frac{2008^{\sin x}}{2008^{\sin x}+2008^{\cos x}} d x=$
  • A
    $0$
  • B
    $\pi$
  • $\frac{\pi}{4}$
  • D
    $\frac{\pi}{2}$

Answer

Correct option: C.
$\frac{\pi}{4}$
(C)
Here, $a =2008$
$\int_0^{\frac{\pi}{2}} \frac{ a ^{\sin x}}{ a ^{\sin x}+ a ^{\cos x}} d x=\int_0^{\frac{\pi}{2}} \frac{ a ^{\cos x}}{ a ^{\sin x}+ a ^{\cos x}} d x=\frac{\pi}{4}$
$\therefore \int_0^{\frac{\pi}{2}} \frac{2008^{\sin x}}{2008^{\sin x}+2008^{\cos x}} d x=\frac{\pi}{4}$

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