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STD 12 - 7.2 definite integral — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - 7.2 definite integral4 Marks
Question
$\int_0^1 {{{\cos }^{ - 1}}x\,dx = } $
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Answer

b
(b) $\int_0^1 {{{\cos }^{ - 1}}x\,\,dx = \left[ {x{{\cos }^{ - 1}}x - \sqrt {1 - {x^2}} } \right]} _0^1 = 1$.

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