_0^1 ^ - 1 x ,dx = - Vidyadip

MCQ

$\int_0^1 {{{\cos }^{ - 1}}x\,dx = } $

A
$0$
✓
$1$
C
$2$
D
None of these

✓

Answer

Correct option: B.

$1$

b
(b) $\int_0^1 {{{\cos }^{ - 1}}x\,\,dx = \left[ {x{{\cos }^{ - 1}}x - \sqrt {1 - {x^2}} } \right]} _0^1 = 1$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from STD 12 - 7.2 definite integral→STD 12 - 7.2 definite integral — all question types→Mathematics STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

Which of the following differentials equation has $\text{y}=\text{C}_{1}\text{e}^{\text{x}}+\text{C}_{2}\text{e}^{-\text{x}}$ as the general solution?

The range of $f(x)=4 \sin ^{-1}\left(\frac{x^2}{x^2+1}\right)$ is

$a > 1,\;\mathop \smallint \limits_1^a \left[ x \right]f'\left( x \right)dx = $

Integration of $\frac{1}{1+(\log_\text{e}\text{x})^2}$ with respect to $\log_\text{e}\text{x}$ is:

If the absolute maximum value of the function $f ( x )$ $=\left( x ^{2}-2 x +7\right) e ^{\left(4 x^{3}-12 x ^{2}-180 x +31\right)}$ in the interval $[-3$, $0]$ is $f (\alpha)$, then.

If $A$ is a square matrix of order $3$ such that $ \operatorname{det}(\mathrm{A})=3 \text { and } $ $ \operatorname{det}\left(\operatorname{adj}\left(-4 \operatorname{adj}\left(-3 \operatorname{adj}\left(3 \operatorname{adj}\left((2 \mathrm{~A})^{-1}\right)\right)\right)\right)\right)=2^{\mathrm{m}} 3^{\mathrm{n}},$ then $m+\mid 2 n$ is equal to:

If ${\sin ^{ - 1}}\left( {\frac{{2a}}{{1 + {a^2}}}} \right) + {\sin ^{ - 1}}\left( {\frac{{2b}}{{1 + {b^2}}}} \right) = 2{\tan ^{ - 1}}x,$ then $x = $

If $\int_{\pi /2}^x {\sqrt {3 - 2{{\sin }^2}u} } \,du + \int_0^y {\cos t\,dt} = 0,$ then $\frac{{dy}}{{dx}} = $

Let $f:[0,1] \rightarrow[0, \infty)$ be a continuous function such that $\int_0^1 f(x) d x=10$. Which of the following statements is NOT necessarily true?

If $f(x)=\left\{\begin{array}{ll}x+a, & x \leq 0 \\ |x-4|, & x>0\end{array}\right.$ and $g(x)=\left\{\begin{array}{ll}x+1 & x<0 \\ (x-4)^{2}+b, & x \geq 0\end{array}\right.$ are continuous on $R$, then $(gof) (2)+( fog) (-2)$ is equal to.