MCQ
$\int_0^1 e ^{2 \log x} dx =$
  • A
    $0$
  • B
    $\frac{1}{2}$
  • $\frac{1}{3}$
  • D
    $\frac{1}{4}$

Answer

Correct option: C.
$\frac{1}{3}$
(C)
$\int_0^1 e^{2 \log x} d x=\int_0^1 e^{\log x^2} d x$
$=\int_0^1 x^2 d x$
$=\left[\frac{x^3}{3}\right]_0^1=\frac{1}{3}$

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