MCQ
$\int_0^{1 / \sqrt{2}} \frac{\sin ^{-1} x}{\left(1-x^2\right)^{\frac{3}{2}}} d x=$
  • A
    $\frac{\pi}{4}+\frac{1}{2} \log 2$
  • $\frac{\pi}{4}-\frac{1}{2} \log 2$
  • C
    $\frac{\pi}{2}+\log 2$
  • D
    $\frac{\pi}{2}-\log 2$

Answer

Correct option: B.
$\frac{\pi}{4}-\frac{1}{2} \log 2$
(B)
Let $I =\int_0^{1 / \sqrt{2}} \frac{\sin ^{-1} x}{\left(1-x^2\right)^{\frac{3}{2}}} d x$
Put $\sin ^{-1} x= t \Rightarrow \frac{1}{\sqrt{1-x^2}} d x= dt$
When $x=0, t =0$ and when $x=\frac{1}{\sqrt{2}}, t =\frac{\pi}{4}$
$\therefore \quad I=\int_0^{\pi / 4} t \cdot \sec ^2 t d t=\frac{\pi}{4}-\frac{1}{2} \log 2$

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