_ 0 ^ 1 ( ^ -1 x)^2 1+x^2 dx= - Vidyadip

MCQ

$\int_{0}^{1}\frac{(\tan^{-1}\text{x})^2}{1+\text{x}^2}\text{dx}=$

A
$1$
B
$\frac{\pi^2}{64}$
✓
$\frac{\pi^2}{192}$
D
None of these

✓

Answer

Correct option: C.

$\frac{\pi^2}{192}$

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