MCQ
$\int_{0}^{20 \pi}(|\sin x|+|\cos x|)^{2} d x$ is equal to.
  • A
    $10(\pi+4)$
  • B
    $10(\pi+2)$
  • C
    $20(\pi-2)$
  • $20(\pi+2)$

Answer

Correct option: D.
$20(\pi+2)$
d
$I=\int_{0}^{20 \pi}(|\sin x|+|\cos x|)^{2} d x \quad ;($ Jack property $)$

$I=40 \int_{0}^{\pi / 2}(\sin x+\cos x)^{2} d x$

$I=40 \int_{0}^{\pi / 2}(1+\sin 2 x) d x$

$I=20[\pi+2]$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

What is the value of $\int_{1}^{\text{e}}\frac{1+\log\text{x}}{\text{x}}\text{dx}\ ?$
Let $y=y(x)$ be the solution of the differential equation, $x y^{\prime}-y=x^{2}(x \cos x+\sin x), x>0$ If $y (\pi)=\pi,$ then $y ^{\prime \prime}\left(\frac{\pi}{2}\right)+ y \left(\frac{\pi}{2}\right)$ is equal to
The function given by $y = | |x| - 1|$ is differentiable for all real numbers except the points
Let $P$ be a matrix of order $3 \times 3$ such that all the entries in $P$ are from the set $\{-1,0,1\}$. Then, the maximum possible value of the determinant of $P$ is. . . . . . .
Let $f : N \rightarrow R : \text{f}(\text{x})=\frac{(2\text{x}-1)}{2}$ and $g : Q \rightarrow R : g(x) = x + 2$ be two functions. Then, $(gof) (\frac{3}{2})$ is:
If the area of the region $S=\left\{(x, y): 2 y-y^2 \leq x^2 \leq 2 y, x \geq y\right\}$ is equal to $\frac{ n +2}{ n +1}-\frac{\pi}{ n -1}$, then the natural number $n$ is equal to $...............$.
The vector $\left( {\hat i \times \vec a.\vec b} \right)\hat i + \left( {\hat j \times \vec a.\vec b} \right)\hat j + \left( {\hat k \times \vec a.\vec b} \right)\hat k$ is equal to
$\int_{}^{} {\sqrt {\frac{{a - x}}{x}} \;dx = } $
The range of the function,

$\mathrm{f}(\mathrm{x})=\log _{\sqrt{5}}(3+\cos \left(\frac{3 \pi}{4}+\mathrm{x}\right)+\cos \left(\frac{\pi}{4}+\mathrm{x}\right)+\cos \left(\frac{\pi}{4}-\mathrm{x}\right)$

$-\cos \left(\frac{3 \pi}{4}-\mathrm{x}\right))$ is :

If $\text{A}=\begin{bmatrix} \text{a} & 0 & 0 \\ 0 & \text{a} & 0 \\ 0 & 0 &\text{a} \end{bmatrix},$ then the value of $\text{|adj A|}$ is: