MCQ
$\int_{\,0}^{\,2a} {f(x)dx = } $
  • A
    $2\int_{\,0}^{\,a} {\,f(x)dx} $
  • B
    $0$
  • $\int_{\,0}^{\,a} {\,f(x)dx + \int_{\,0}^{\,a} {\,f(2a - x)dx} } $
  • D
    $\int_{\,0}^{\,a} {f(x)dx + } \int_{\,0}^{\,2a} {\,f(2a - x)dx} $

Answer

Correct option: C.
$\int_{\,0}^{\,a} {\,f(x)dx + \int_{\,0}^{\,a} {\,f(2a - x)dx} } $
c
(c) It is a fundamental property.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Choose the correct option from given four options : $\int\frac{\cos2\text{x}-\cos2\theta}{\cos\text{x}-\cos\theta}\text{dx}$ is equal to :
If $\int {({x^3} - 2{x^2} + 5){e^{3x}}\,dx} \,$ $= e^{3x} (Ax^3 + Bx^2 + Cx + D)$ then the statement which is incorrect is
The value of $\int_{}^{} {\frac{{{x^3}}}{{\sqrt {1 + {x^4}} }}\;dx} $ is
Suppose that

Box-$I$ contains $8$ red, $3$ blue and $5$ green balls,

Box-$II$ contains $24$ red, $9$ blue and $15$ green balls,

Box-$III$ contains $1$ blue, $12$ green and $3$ yellow balls,

Box-$IV$ contains $10$ green, $16$ orange and $6$ white balls.

A ball is chosen randomly from Box-I ; call this ball $b$. If $b$ is red then a ball is chosen randomly from Box-$II$, if $b$ is blue then a ball is chosen randomly from Box-$III$, and if $b$ is green then a ball is chosen randomly from Box-$IV$. The conditional probability of the event 'one of the chosen balls is white' given that the event 'at least one of the chosen balls is green' has happened, is equal to

Choose the correct answer from the given four options.Which of the following is the general solution of $\frac{\text{d}^2\text{y}}{\text{d}\text{x}^2}-2\frac{\text{d}\text{y}}{\text{d}\text{x}}+\text{y}=0?$
Area of the region bounded by rays |x| + y = 1 and X - axis is ___________.
If ${\Delta _1} = \left| {\begin{array}{*{20}{c}}
  {{b^5}{c^6}\left( {{c^3} - {b^3}} \right)}&{{a^4}{c^6}\left( {{a^3} - {c^3}} \right)}&{{a^4}{b^5}\left( {{b^3} - {a^3}} \right)} \\ 
  {{b^2}{c^3}\left( {{b^6} - {c^6}} \right)}&{a{c^3}\left( {{c^6} - {a^6}} \right)}&{a{b^2}\left( {{a^6} - {b^6}} \right)} \\ 
  {{b^2}{c^3}\left( {{c^3} - {b^3}} \right)}&{a{c^3}\left( {{a^3} - {c^3}} \right)}&{a{b^2}\left( {{b^3} - {a^3}} \right)} 
\end{array}} \right|$ and ${\Delta _2} = \left| {\begin{array}{*{20}{c}}
  a&{{b^2}}&{{c^3}} \\ 
  {{a^4}}&{{b^5}}&{{c^6}} \\ 
  {{a^7}}&{{b^8}}&{{c^9}} 
\end{array}} \right|$ then ${\Delta _1}{\Delta _2}$ is equal to
If $A = \left[ {\begin{array}{*{20}{c}}
1&1\\
1&1
\end{array}} \right]$ and $\det ({A^n} - I) = 1 - {\lambda ^n}\,,\,n \in N$ then $\lambda $ is
If $\int \frac{d x}{\left(x^{2}+x+1\right)^{2}}=a \tan ^{-1}\left(\frac{2 x+1}{\sqrt{3}}\right)+b\left(\frac{2 x+1}{x^{2}+x+1}\right)+C$ $x>0$ where $C$ is the constant of integration, then the value of $9(\sqrt{3} \mathrm{a}+\mathrm{b})$ is equal to ... .
Choose the correct answer from the given four options : Area of the region in the first quadrant enclosed by the $x-$ axis, the line $y = x $ and the circle $x^2 + y^2 = 32$ is: