MCQ
$\int_0^{2\pi } {\frac{{\sin 2\theta }}{{a - b\,\cos \theta }}\,d\theta = } $
- A$1$
- B$2$
- C$\frac{\pi }{4}$
- ✓$0$
==> I $ = - \int_0^{2\pi } {\frac{{\sin 2\theta }}{{a - b\cos \theta }}d\theta } $
$ \Rightarrow \,\,2I = 0 $
$\Rightarrow \,\,\int_0^{2\pi } {\frac{{\sin 2\theta }}{{a - b\cos \theta }}d\theta = 0} $..
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