- A$1$
- B$2\sqrt 2 $
- ✓$0$
- DNone of these
==> $I = 2\int_0^\pi {{e^t}\sin \left( {t + \frac{\pi }{4}} \right)dt} $
$= 2\left[ {\frac{{{e^t}}}{{\sqrt {1 + 1} }}\sin \left( {t + \frac{\pi }{4} - {{\tan }^{ - 1}}\frac{1}{1}} \right)} \right]_0^\pi $
$ = \frac{2}{{\sqrt 2 }}\left[ {{e^t}\sin t} \right]_0^\pi = \frac{2}{{\sqrt 2 }}[0] = 0$.
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$ \frac{\pi}{2}$
$ + sin^{-1} \left\{ \,\frac{1}{{\sqrt {13} }}(2\cos x + 3\sin x)\,\,\,\right\} $ w.r.t. at $x = \frac{3}{4}$ is :
$\begin{bmatrix}-5&-7\\3&3\end{bmatrix}=\begin{bmatrix}1&-7\\0&3\end{bmatrix}\begin{bmatrix}2&0\\1&1\end{bmatrix}$
$\begin{bmatrix}-5&-7\\3&3\end{bmatrix}=\begin{bmatrix}1&2\\1&-7\end{bmatrix}\begin{bmatrix}2&0\\1&1\end{bmatrix}$
$\begin{bmatrix}4&2\\-5&-7\end{bmatrix}=\begin{bmatrix}1&2\\-3&-3\end{bmatrix}\begin{bmatrix}2&0\\1&1\end{bmatrix}$