_ ,0 ^ ,2 | x| ,dx = - Vidyadip

MCQ

$\int_{\,0}^{\,2\pi } {|\sin x|\,dx = } $

A
$0$
B
$1$
C
$2$
✓
$4$

✓

Answer

Correct option: D.

$4$

d
(d) $\int_0^{2\pi } {|\sin x|dx = \int_0^\pi {\sin x\,dx + \int_\pi ^{2\pi } { - \sin x\,dx} } } $

$ = [ - \cos x]_0^\pi + [\cos x]_\pi ^{2\pi } = 1 + 1 + 1 + 1 = 4$.

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