MCQ
$\int_0^\infty {{e^{ - 2x}}(\sin 2x + \cos 2x)\,dx = } $
- A$1$
- B$0$
- ✓$\frac{1}{2}$
- D$\infty $
$ = \left[ { - {e^{ - x}}\frac{{\cos 2x}}{2}} \right]_0^\infty - \int_0^\infty {\left( { - 2{e^{ - 2x}}} \right)\,} \left( {\frac{{ - \cos 2x}}{2}} \right){\rm{ }}dx$
$ + \int_0^\infty {{e^{ - 2x}}\cos 2x\,dx} $
$ = \frac{1}{2}$.
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$a_{i j}= 1 , \quad\quad\text { if } i=j$
$\quad\quad-x ,\quad \text { if }|i-j|=1$
$\quad\quad2 x+1, \text { otherwise }$
Let a function f: $\mathrm{R} \rightarrow \mathrm{R}$ be defined as $\mathrm{f}(\mathrm{x})=\operatorname{det}(\mathrm{A})$. Then the sum of maximum and minimum values of $f$ on $R$ is equal to: