MCQ
$\int_0^{\pi /2} {{{\cos }^2}x\,dx = } $
  • A
    $1 - \frac{\pi }{4}$
  • B
    $1 + \frac{\pi }{4}$
  • $\frac{\pi }{4}$
  • D
    $\frac{\pi }{2}$

Answer

Correct option: C.
$\frac{\pi }{4}$
c
(c) Using gamma function,

$\int_0^{\pi /2} {\,\,{{\cos }^2}x\,dx} $

$=\frac{{\Gamma \left( {\frac{3}{2}} \right)\Gamma \left( {\frac{1}{2}} \right)}}{{2\Gamma (2)}}$

$= \frac{{\frac{1}{2}\Gamma \left( {\frac{1}{2}} \right)\Gamma \left( {\frac{1}{2}} \right)}}{{2.1.\Gamma (1)}} = \frac{\pi }{4}$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If two events $A$ and $B$ are such that $P\,(A + B) = \frac{5}{6},$ $P\,(AB) = \frac{1}{3}\,$ and $P\,(\bar A) = \frac{1}{2},$ then the events $A$ and $B$ are
A circle in inscribed in an equilateral triangle of side of length $12.$ If the area and perimeter of any square inscribed in this circle are $m$ and $n,$ respectively, then $m + n^2$ is equal to
Two dice are thrown together. The probability that at least one will show its digit $6$ is
In the expansion of ${\left( {\frac{{1 + x}}{{1 - x}}} \right)^2}$, the coefficient of ${x^n}$ will be
If in a lottary there are $5$ prizes and $20$ blanks, then the probability of getting a prize is
Let $f: R \rightarrow R$ be a function defined by$f(x)=\left\{\begin{array}{l}\max \left\{t^{3}-3 t\right\} ; x \leq 2 \\ t \leq x \\ x^{2}+2 x-6 ; 2 < x < 3 \\ {[x-3]+9 ; 3 \leq x \leq 5} \\ 2 x+1 \quad ; \quad x > 5\end{array}\right\}$ Where $[t]$ is the greatest integer less than or equal to $t$. Let $m$ be the number of points where $f$ is not differentiable and $I =\int\limits_{-2}^{2} f( x ) dx$. Then the ordered pair $( m , I )$ is equal to
If ${S_n} = nP + \frac{1}{2}n(n - 1)Q$, where ${S_n}$ denotes the sum of the first $n$ terms of an $A.P.$, then the common difference is
Let $A$ and $B$ be two sets in the universal set. Then $A - B$ equals
$\left| {\,\begin{array}{*{20}{c}}{a - b}&{b - c}&{c - a}\\{x - y}&{y - z}&{z - x}\\{p - q}&{q - r}&{r - p}\end{array}\,} \right| = $
Let $S=\{1,2,3,4,5,6,7,8,9,10\}$. Define $f: S \rightarrow S$ as $f(n)=\left\{\begin{array}{cc}2 n, & \text { if } n=1,2,3,4,5 \\ 2 n-11 & \text { if } n=6,7,8,9,10\end{array}\right.$. Let $g : S \rightarrow S$ be a function such that $f o g(n)=\left\{\begin{array}{ll}n+1 & \text {, if } n \text { is odd } \\ n-1 & \text {, if } n \text { is even }\end{array}\right.$, then $g (10)(( g (1)+ g (2)+ g (3)+ g (4)+ g (5))$ is equal to