_ ,0 ^ , /2 2x x ,dx is equal to - Vidyadip

MCQ

$\int_{\,0}^{\,\pi /2} {\sin 2x\log \tan x\,dx} $ is equal to

A
$\pi $
B
$\pi /2$
✓
$0$
D
$2\pi $

✓

Answer

Correct option: C.

$0$

c
(c) $I = \int_0^{\pi /2} {\,\,\sin 2x\log \tan x\,\,dx} $,

$I = \int_0^{\pi /2} {\sin 2\,\left( {\frac{\pi }{2} - x} \right)\log \tan \left( {\frac{\pi }{2} - x} \right)\,\,dx} $,

$[\because \int_{0}^{a}{f\,(x)\,dx=\int_{0}^{a}{f\,(a-x)\,dx]}}$

$ = \int_0^{\pi /2} {\,\,\,\,\,\sin 2x\log \cot x\,\,dx} $

$ = - \int_0^{\pi /2} {\,\,\,\,\,\sin 2x\log \tan x\,\,dx} $

$\therefore I = - I\,\,==> 2I = 0$ $ \Rightarrow I = 0.$

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