MCQ
$\int_0^{\pi /2} {{{\sin }^5}x\,dx = } $
- ✓$\frac{8}{{15}}$
- B$\frac{4}{{15}}$
- C$\frac{{8\sqrt \pi }}{{15}}$
- D$\frac{{8\pi }}{{15}}$
✓
Answer
Correct option: A.
$\frac{8}{{15}}$
a
(a)$\int_0^{\pi /2} {{{\sin }^5}xdx = \frac{{\Gamma (3).\Gamma (1/2)}}{{2.\Gamma (7/2)}} = \frac{8}{{15}}} $.
(a)$\int_0^{\pi /2} {{{\sin }^5}xdx = \frac{{\Gamma (3).\Gamma (1/2)}}{{2.\Gamma (7/2)}} = \frac{8}{{15}}} $.
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