MCQ
$\int_0^{\pi / 2} \sin ^6 x \cos ^2 x \cdot d x=$
- A$\frac{7 \pi}{256}$
- B$\frac{3 \pi}{256}$
- ✓$\frac{5 \pi}{256}$
- D$\frac{-5 \pi}{256}$
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