MCQ
$\int_0^{\pi /3} {\cos 3x\,dx = } $
- A$\pi $
- ✓$0$
- C$\frac{\pi }{2}$
- D$\frac{\pi }{4}$
✓
Answer
Correct option: B.
$0$
b
(b) Required value is $\left[ {\frac{{\sin 3x}}{3}} \right]_0^{\pi /3} = 0$.
(b) Required value is $\left[ {\frac{{\sin 3x}}{3}} \right]_0^{\pi /3} = 0$.
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