MCQ
$\int_0^{\pi / 4} \frac{\cos ^2 x \sin ^2 x}{\left(\cos ^3 x+\sin ^3 x\right)^2} d x$ is equal to
- A$1 / 12$
- B$1 / 9$
- ✓$1 / 6$
- D$1 / 3$
$\int_0^{\pi / 4} \frac{\tan ^2 x \sec ^2 x d x}{\left(1+\tan ^3 x\right)^2} d x$
Let $1+\tan ^3 \mathrm{x}=\mathrm{t}$
$\tan ^2 \mathrm{x} \sec ^2 \mathrm{x} d \mathrm{x}=\frac{\mathrm{dt}}{3}$
$\frac{1}{3} \int_1^2 \frac{\mathrm{dt}}{\mathrm{t}^2}=\frac{1}{6}$
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