MCQ
$\int_0^{\pi /4} {{{\tan }^2}x\,dx = } $
- ✓$1 - \frac{\pi }{4}$
- B$1 + \frac{\pi }{4}$
- C$\frac{\pi }{4} - 1$
- D$\frac{\pi }{4}$
$ = \int_0^{\pi /4} {{{\sec }^2}xdx - \int_0^{\pi /4} {\,\,1dx} } $
$= [\tan x]_0^{\pi /4} - [x]_0^{\pi /4} = 1 - \frac{\pi }{4}$.
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| $X$ | $1$ | $2$ | $3$ | $4$ | $5$ |
| $P(X)$ | $K$ | $2K$ | $2K$ | $3K$ | $K$ |
અહી $\mathrm{p}=\mathrm{P}(1\,<\mathrm{X}\,<\,4 \mid \mathrm{X}\,<\,3)$. જો $5 \mathrm{p}=\lambda \mathrm{K}$ હોય તો $\lambda$ ની કિમંત મેળવો.