MCQ
$\int_0^{\pi / 8} \tan ^2(2 x) d x$ is equal to
  • $\frac{4-\pi}{8}$
  • B
    $\frac{4+\pi}{8}$
  • C
    $\frac{4-\pi}{4}$
  • D
    $\frac{4-\pi}{2}$

Answer

Correct option: A.
$\frac{4-\pi}{8}$
$\text {Let } I=\int_0^{\pi / 8} \tan ^2(2 x) d x=\int_0^{\pi / 8}\left(\sec ^2(2 x)-1\right) d x$
$=\left(\frac{1}{2} \tan 2 x-x\right)_0^{\pi / 8}$
$=\frac{1}{2} \tan 2\left(\frac{\pi}{8}\right)-\frac{\pi}{8}$
$=\frac{1}{2} \tan \frac{\pi}{4}-\frac{\pi}{8}$
$=\frac{1}{2}-\frac{\pi}{8}=\frac{4-\pi}{8}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Let $a, \lambda, \mu \in \mathbb{R}$. Consider the system of linear equations

$a x+2 y=\lambda$

$3 x-2 y=\mu$Which of the following statement($s$) is(are) correct?

($A$) If $a=-3$, then the system has infinitely many solutions for all values of $\lambda$ and $\mu$

($B$) If $a \neq-3$, then the system has a unique solution for all values of $\lambda$ and $\mu$

($C$) If $\lambda+\mu=0$, then the system has infinitely many solutions for $a=-3$

($D$) If $\lambda+\mu \neq 0$, then the system has no solution for $a=-3$

The value of the determinant $\left|\begin{array}{ccc}6 & 0 & -1 \\ 2 & 1 & 4 \\ 1 & 1 & 3\end{array}\right|$ is
Let M be the set of all 2 × 2 matrices with entries from the set R of real numbers. Then, the function f : M→ R defined by f(A) = |A| for every A ∈ M, is:
If a line makes angles $\alpha,\beta,\gamma$ with the axis then $\cos 2\alpha+ \cos 2\beta +\cos 2\gamma=$
Let the functions $:(-1,1) \rightarrow R$ and $g:(-1,1) \rightarrow(-1,1)$ be defined by $f(x)=|2 x-1|+|2 x+1|$ and $g(x)=x-[x]$,

where $[x]$ denotes the greatest integer less than or equal to $x$. Let $f \circ:(-1,1) \rightarrow R$ be the composite function defined by $(f \circ g)(x)=f(g(x))$. Suppose $c$ is the number of points in the interval $(-1,1)$ at which $f \circ g$ is NOT continuous, and suppose $d$ is the number of points in the interval $(-1,1)$ at which $f \circ g$ is $NOT$ differentiable. Then the value of $c+d$ is. . . . .

Let $C_{1}$ be the curve obtained by the solution of differential equation $2 xy \frac{ dy }{ dx }= y ^{2}- x ^{2}, x > 0$ Let the curve $C _{2}$ be the solution of $\frac{2 x y}{x^{2}-y^{2}}=\frac{d y}{d x} .$ If both the curves pass through $(1,1),$ then the area enclosed by the curves $C_{1}$ and $C _{2}$ is equal to :
Area bounded by the curvey $\text{y}=\text{x}+\sin\text{x}$ and its inverse function between the ordinates $\text{x}=0$ and $\text{x}=2\pi$ is:
The solution of the differential equation $ydx - \left( {x + 2{y^2}} \right)dy = 0$ is $x\, = f(y)$. If $f(-1)\, = 1$, then $f(1)$ is equal to
If $3i + 4j$ and $ - 5i + 7j$ are the vector sides of any triangle, then its area is given by
Let $\mathrm{f}:(-1, \infty) \rightarrow \mathrm{R}$ be defined by $\mathrm{f}(0)=1$ and $f(x)=\frac{1}{x} \log _{e}(1+x), x \neq 0 .$ Then the function $f$