MCQ
$\int_{\,0}^{\,\pi } {{e^{{{\sin }^2}x}}{{\cos }^3}x\,dx} $ is equals to
  • A
    $ - 1$
  • $0$
  • C
    $1$
  • D
    $\pi $

Answer

Correct option: B.
$0$
b
(b) $I = \int_0^\pi {{e^{{{\sin }^2}x}}{{\cos }^3}x\,\,dx} $

$ \Rightarrow I = \int_0^\pi {{e^{{{\sin }^2}(\pi - x)}}{{\cos }^3}(\pi - x)\,} dx$ ..$(i)$

$ \Rightarrow I = - \int_0^\pi {{e^{{{\sin }^2}x}}{{\cos }^3}x\,dx} $ ..$(ii)$

Adding $(i)$ and $(ii),$ we get

$2I = 0$ ==> $I = 0$.

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