MCQ
$\int_{\,0}^{\,\pi } {{e^{{{\sin }^2}x}}{{\cos }^3}x\,dx} $ is equals to
- A$ - 1$
- ✓$0$
- C$1$
- D$\pi $
$ \Rightarrow I = \int_0^\pi {{e^{{{\sin }^2}(\pi - x)}}{{\cos }^3}(\pi - x)\,} dx$ ..$(i)$
$ \Rightarrow I = - \int_0^\pi {{e^{{{\sin }^2}x}}{{\cos }^3}x\,dx} $ ..$(ii)$
Adding $(i)$ and $(ii),$ we get
$2I = 0$ ==> $I = 0$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\mathrm{Q}=\mathrm{A}^{\mathrm{T}} \mathrm{BA}$, then the inverse of the matrix $\mathrm{A} \mathrm{Q}^{2021} \mathrm{~A}^{\mathrm{T}}$ is equal to :
$\frac{d y}{d x}+12 y=\cos \left(\frac{\pi}{12} x\right), y(0)=0 .$
Then, which of the following statements is/are $TRUE$?