Maharashtra BoardEnglish MediumSTD 12 ScienceMathsDefinite Integration2 Marks
MCQ
$\int_0^\pi x \sin x d x=$
✓
$\pi$
B
$0$
C
1
D
$\pi^2$
✓
Answer
Correct option: A.
$\pi$
(A) Let $I =\int_0^\pi x \sin x d x$ … (i) $\therefore \quad I =\int_0^\pi(\pi-x) \sin (\pi-x) d x$ $\ldots\left[\because \int_0^{ a } f (x) d x=\int_0^{ a } f ( a -x) d x\right]$ $\therefore \quad I=\int_0^\pi(\pi-x) \sin x d x$ ...(ii) Adding (i) and (ii), we get $2 I =\pi \int_0^\pi \sin x d x=\pi[-\cos x]_0^\pi=2 \pi$ $\Rightarrow I =\pi$
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