MCQ
$\int_0^\pi {x\sin x\,dx = } $
  • $\pi $
  • B
    $0$
  • C
    $1$
  • D
    ${\pi ^2}$

Answer

Correct option: A.
$\pi $
a
(a) $I = \int_0^\pi {x\sin xdx = \int_0^\pi {(\pi - x)\sin x\,dx} } $

==> $2I = \pi \int_0^\pi {\sin xdx = \pi [ - \cos x]_0^\pi \Rightarrow I = \pi } $.

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