MCQ
$\int_0^\pi {x\sin x\,dx = } $
- ✓$\pi $
- B$0$
- C$1$
- D${\pi ^2}$
==> $2I = \pi \int_0^\pi {\sin xdx = \pi [ - \cos x]_0^\pi \Rightarrow I = \pi } $.
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