MCQ
$\int_{0}^{\frac{\pi}{2}}\sqrt{1+\sin2\text{x}}\text{dx}$ is equal to:
- A$2\sqrt{2}$
- B$2(\sqrt{2+1})$
- ✓$0$
- D$2(\sqrt{2-1})$
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$(A)$ $f(x)$ is continuous at $x=-\frac{\pi}{2}$
$(B)$ $f(x)$ is not differentiable at $x=0$
$(C)$ $f(x)$ is differentiable at $x=1$
$(D)$ $ f(x)$ is differentiable at $x=-\frac{3}{2}$