MCQ
$\int_1^2 \frac{1}{x^2} e^{\frac{1}{x}} \cdot d x=$
  • A
    $\sqrt{e}+1$
  • B
    $\sqrt{e}-1$
  • $\sqrt{e}(\sqrt{e}-1)$
  • D
    $\frac{\sqrt{e}-1}{e}$

Answer

Correct option: C.
$\sqrt{e}(\sqrt{e}-1)$
$\sqrt{ } e(\sqrt{e}-1)$

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