MCQ
$\int_1^3(x-1)(x-2)(x-3) d x$ =
  • A
    3
  • B
    2
  • C
    1
  • $0$

Answer

Correct option: D.
$0$
(D)
$\int_1^3(x-1)(x-2)(x-3) d x$
$=\int_1^3\left(x^3-6 x^2+11 x-6\right) d x$
$=\left[\frac{x^4}{4}-\frac{6 x^3}{3}+\frac{11 x^2}{2}-6 x\right]_1^3=0$

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