- A$1 - \frac{1}{e}$
- ✓$2\,\left( {1 - \frac{1}{e}} \right)$
- C${e^{ - 1}} - 1$
- DNone of these
$ = [x - x\log x]_{1/e}^1 + [x\log x - x]_1^e$
$ = (1 - 0) - \left\{ {\frac{1}{e} - \frac{1}{e}( - 1)} \right\} + e - e + 1$
$ = 2 - \frac{2}{e} = 2\left( {1 - \frac{1}{e}} \right)$.
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2
3
$-\frac{3}{2}$
None of these
$1.$ The real number $s$ lies in the interval
$(A)$ $\left(-\frac{1}{4}, 0\right)$ $(B)$ $\left(-11,-\frac{3}{4}\right)$
$(C)$ $\left(-\frac{3}{4},-\frac{1}{2}\right)$ $(D)$ $\left(0, \frac{1}{4}\right)$
$2.$ The area bounded by the curve $y=f(x)$ and the lines $x=0, y=0$ and $x=t$, lies in the interval
$(A)$ $\left(\frac{3}{4}, 3\right)$ $(B)$ $\left(\frac{21}{64}, \frac{11}{16}\right)$
$(C)$ $(9,10)$ $(D)$ $\left(0, \frac{21}{64}\right)$
$3.$ The function $f^{\prime}(x)$ is
$(A)$ increasing in $\left(-t,-\frac{1}{4}\right)$ and decreasing in $\left(-\frac{1}{4}, t\right)$
$(B)$ decreasing in $\left(-t,-\frac{1}{4}\right)$ and increasing in $\left(-\frac{1}{4}, t\right)$
$(C)$ increasing in (-t, t) $(D)$ decreasing in ( $-\mathrm{t}, \mathrm{t})$
Give the answer question $1,2$ and $3.$