MCQ
$\int\frac{2\text{x}\log(1+\text{x}^2)}{1+\text{x}^2}\text{dx:}$
  • A
    $\log(1+\text{x}^2)+\text{c}$
  • $\frac{[\log(1+\text{x}^2)^2]}{2}+\text{c}$
  • C
    $2\log(1+\text{x}^2)+\text{c}$
  • D
    None of these

Answer

Correct option: B.
$\frac{[\log(1+\text{x}^2)^2]}{2}+\text{c}$
$\int\frac{2\text{x}\log(1+\text{x}^2)}{1+\text{x}^2}\text{dx}$

Let $\log(1+\text{x}^2) =\text{z}$ and $\frac{\text{2x}}{1+\text{x}^2}\text{dx}=\text{dz}$ Using these in the above integration we get,

$=\int\text{z, }{\text{dz}}$

$\frac{\text{z}^2}{2}+\text{c}$ [Where c is integrating constant]

$=\frac{[\log(1+\text{x}^2)^2]}{2}+\text{c}$

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