MCQ
$\int\big(1+5\text{x}+10\text{x}^2+10\text{x}^3+5\text{x}^4+\text{x}^5\big)\text{dx}=\frac{(1+\text{x})\text{p}}{6}+\text{c}$ then $p$ is :
  • A
    $5$
  • $6$
  • C
    $7$
  • D
    $8$

Answer

Correct option: B.
$6$
Given, $\int\big(1+5\text{x}+10\text{x}^2+10\text{x}^3+5\text{x}^4+\text{x}^5\big)\text{dx}$
$\int(\text{x+1})^5\text{dx}\ [$by binomial theorem$]$
$=(\text{x+1})^5\text{dx}=\frac{(\text{x+1})6}{6}+\text{c}$
So, the value of $p = 6$

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