Question
Integrate the following w.r.t. x:
$\frac{x^2}{\sqrt{1-x^6}}$
$\frac{x^2}{\sqrt{1-x^6}}$
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$\frac{d^4 y}{d x^4}+\sin \left(\frac{d y}{d x}\right)=0$
$\sqrt[3]{1+\left(\frac{d y}{d x}\right)^2}=\frac{d^2 y}{d x^2}$