Question
Integrate the function: $(4 x+2) \sqrt{x^{2}+x+1}$

Answer

Let x2 + x + 1 = t
Differentiating both sides, we get,
$\Rightarrow$ (2x + 1)dx = dt
Therefore
$\Rightarrow \int(4 x+2) \sqrt{x^{2}+x+1} d x=\int 2 \sqrt{t} d t$ 
$=2 \int \sqrt{t} d t$ 
$= 2\left(\frac{t^{\frac{3}{2}}}{\frac{3}{2}}\right)+C$
$=\frac{4}{3}\left(x^{2}+x+1\right)^{\frac{3}{2}}+C$

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