Gujarat BoardEnglish MediumSTD 12 ScienceMathsIntegrals2 Marks
Question
Integrate the function: $(4 x+2) \sqrt{x^{2}+x+1}$
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Answer
Let x2 + x + 1 = t Differentiating both sides, we get, $\Rightarrow$ (2x + 1)dx = dt Therefore $\Rightarrow \int(4 x+2) \sqrt{x^{2}+x+1} d x=\int 2 \sqrt{t} d t$ $=2 \int \sqrt{t} d t$ $= 2\left(\frac{t^{\frac{3}{2}}}{\frac{3}{2}}\right)+C$ $=\frac{4}{3}\left(x^{2}+x+1\right)^{\frac{3}{2}}+C$
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