Question
Integrate the function: $\frac{1}{{x - \sqrt x }}$
Putting $\sqrt x = t$
$ \Rightarrow x = {t^2}$
$\Rightarrow \frac{{dx}}{{dt}} = 2t$
$ \Rightarrow dx = 2tdt$
$\therefore $ From eq. (i),
$I = \int {\frac{1}{{{t^2} - t}}2t} dt$
$= 2\int {\frac{t}{{t\left( {t - 1} \right)}}} dt$
$ = 2\int {\frac{1}{{\left( {t - 1} \right)}}} dt$
= 2 log |t - 1| + c
$ = 2\log \left| {\sqrt x - 1} \right| + c$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.