Question
Integrate the function $\int {{{\cos }^3}x{e^{\log \sin x}}}$
$\because {e^{\log \theta }} = \theta $
$\therefore {e^{\log \sin x}} = \sin x$
$ I= \int {{{\cos }^3}} x.\sin xdx$
Put cos x = t
$ - \sin x\,dx = dt$
$\sin x\,dx = - dt$
$I = \int { - {t^3}dt} $
$ = - \frac{{{t^4}}}{4} + c = - \frac{{{{\cos }^4}x}}{4} + c$
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