Question
Integrate the function: $\sec^2 (7 – 4x)$

Answer

Let $7 – 4x = t$
$\Rightarrow -4dx = dt$
$\Rightarrow \int \sec ^{2}(7-4 x) d x=\frac{-1}{4} \int \sec ^{2} t d t$ 
$\Rightarrow \frac{-1}{4}(\tan t)+C$ 
$\Rightarrow \frac{-1}{4} \tan (7-4 x)+C$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free