Question
Integrate the function sin mx w.r.t. x.
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Answer
We know that derivative of mx is m.
Thus, we make the substitution mx = t so that mdx = dt.
Therefore, $\int \sin m x d x=\frac{1}{m} \int \sin t d t$ $=-\frac{1}{m} \cos t+\mathrm{C}=-\frac{1}{m} \cos m x+\mathrm{C}$
Thus, we make the substitution mx = t so that mdx = dt.
Therefore, $\int \sin m x d x=\frac{1}{m} \int \sin t d t$ $=-\frac{1}{m} \cos t+\mathrm{C}=-\frac{1}{m} \cos m x+\mathrm{C}$
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