Question
Integrate the function: $\sqrt{\sin 2 x} \cos 2 x$

Answer

Let sin2x = t
$\Rightarrow$ 2cos2xdx = dt
$=\int \sqrt{\sin 2 x} \cos 2 x d x=\frac{1}{2} \int \sqrt{t} d t$ 
$\Rightarrow \frac{1}{2}\left(\frac{t^{\frac{3}{2}}}{\frac{3}{2}}\right)+C$ 
$\Rightarrow \frac{1}{3}(\sin 2 x)^{\frac{3}{2}}+C$

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