Question
Integrate the functions in Exercises:
$\text{e}^{2\text{x}+3}$

Answer

$\int\text{e}^{2\text{x}+3}\text{ dx}=\frac{\text{e}^{2\text{x}+3}}{2\rightarrow \text{Coeff. of x }}+\text{c} \ \ \ \ \ \ \ \ \because \int\text{e}^{\text{ax}+\text{b}}\text{ dx}=\frac{\text{e}^{\text{ax}+\text{b}}}{\text{a}} $
$=\frac{1}{2}\text{e}^{2\text{x}+3}+\text{c} $

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