MCQ
Integration of $\left(\sqrt{x}+\frac{1}{\sqrt{x}}\right)$ with respect to $x$ :
  • A
    $\frac{1}{3} x^{\frac{1}{3}}+2 x^{\frac{1}{2}}+ C$
  • B
    $\frac{2}{3} x^{\frac{2}{3}}+\frac{1}{2} x^2+ C$
  • $\frac{2}{3} x^{\frac{3}{2}}+2 x^{\frac{1}{2}}+ C$
  • D
    $\frac{3}{2} x^{\frac{3}{2}}+\frac{1}{2} x^{\frac{1}{2}}+ C$

Answer

Correct option: C.
$\frac{2}{3} x^{\frac{3}{2}}+2 x^{\frac{1}{2}}+ C$
(C)
Let $I =\int\left(\sqrt{x}+\frac{1}{\sqrt{x}}\right) d x$
$
\begin{array}{l}
=\int\left(x^{\frac{1}{2}}+x^{-\frac{1}{2}}\right) d x \\
=\frac{x^{\frac{3}{2}}}{\frac{3}{2}}+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+C
\end{array}
$
$
=\frac{2}{3} x^{\frac{3}{2}}+2 x^{\frac{1}{2}}+C
$
Hence correct option is (C).

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