Question
$\int\left(\sin ^{-1} x+\cos ^{-1} x\right) d x$ is equal to :

Answer

(C)
$
\begin{aligned}
\int\left(\sin ^{-1} x+\cos ^{-1} x\right) d x=\int \frac{\pi}{2} \cdot d x & =\frac{\pi}{2} \int d x \\
& =\frac{\pi}{2} \cdot x+C
\end{aligned}
$
Hence option (A) is correct.

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