MCQ
$\int\limits_{\frac{1}{2}}^2 {\frac{1}{x}{{\tan }^{2015}}\left( {x - \frac{1}{x}} \right)dx} $ is equal to
  • A
    $\frac{1}{2}$
  • B
    $2$
  • $0$
  • D
    $\frac{1}{2015}$

Answer

Correct option: C.
$0$
c
Put $x = \frac{1}{t}$ we get $I = - I \Rightarrow I =0$

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