- A$\frac{{\pi - 2}}{2}$
- B$\frac{{\pi - 1}}{2}$
- C$\frac{{\pi - 2}}{4}$
- ✓$\frac{{\pi - 1}}{4}$
$\int_0^\infty {\frac{{{x^3}dx}}{{(1 + x){{\left( {1 + {x^2}} \right)}^2}}}} $
put $x=\tan \theta$
$\int_0^{\frac{\pi }{2}} {\frac{{{{\tan }^3}\theta {{\sec }^2}\theta d\theta }}{{(1 + \tan \theta ){{\sec }^2}\theta \cdot {{\sec }^2}\theta }}} $
$I=\int_{0}^{\frac{\pi}{2}} \frac{\sin ^{3} \theta d \theta}{\cos \theta+\sin \theta}$
apply king
$I=\int_{0}^{\frac{\pi}{2}} \frac{\cos ^{3} \theta d \theta}{\cos \theta+\sin \theta}$
on add $2 \mathrm{I}=\int_{0}^{\pi / 2}\left(\cos ^{2} \theta+\sin ^{2} \theta-\cos \theta \sin \theta\right)$
$=\frac{\pi}{2}+\left[\frac{\cos 2 \theta}{4}\right]_{0}^{\pi / 2}$
$I=\frac{\pi-1}{4}$
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Then a possible value to $\mathrm{p}+\mathrm{q}$ is :
(where $c $ is constant of integration)