MCQ
$\int_{\pi /4}^{\pi /2} {{\rm{cose}}{{\rm{c}}^2}xdx = } $
- A$ - 1$
- ✓$1$
- C$0$
- D$\frac{1}{2}$
✓
Answer
Correct option: B.
$1$
b
(b) $\int_{\pi /4}^{\pi /2} {{\rm{cose}}{{\rm{c}}^2}} x\;dx = \left[ { - \cot x} \right]_{\pi /4}^{\pi /2}$
(b) $\int_{\pi /4}^{\pi /2} {{\rm{cose}}{{\rm{c}}^2}} x\;dx = \left[ { - \cot x} \right]_{\pi /4}^{\pi /2}$
$ = - \left[ {\cot \frac{\pi }{2} - \cot \frac{\pi }{4}} \right] = 1$.
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