_ /4 ^ /2 cose c ^2 xdx = - Vidyadip

MCQ

$\int_{\pi /4}^{\pi /2} {{\rm{cose}}{{\rm{c}}^2}xdx = } $

A
$ - 1$
✓
$1$
C
$0$
D
$\frac{1}{2}$

✓

Answer

Correct option: B.

$1$

b
(b) $\int_{\pi /4}^{\pi /2} {{\rm{cose}}{{\rm{c}}^2}} x\;dx = \left[ { - \cot x} \right]_{\pi /4}^{\pi /2}$

$ = - \left[ {\cot \frac{\pi }{2} - \cot \frac{\pi }{4}} \right] = 1$.

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