Question
$\int\sin^2(2\text{x}+5)\text{dx}$

Answer

$\int\sin^2(2\text{x}+5)\text{dx}$
$=\int\Big(\frac{1-\cos(4\text{x}+10)}{2}\Big)\text{dx}$ $\Big[\therefore\sin^2\text{A}=\frac{1-\cos2\text{A}}{2}\Big]$
$=\frac{1}{2}\int(1-\cos(4\text{x}+10))\text{dx}$
$=\frac{1}{2}\Big[\text{x}-\frac{\sin(4\text{x}+10)}{4}\Big]+\text{C}$
$=\frac{1}{2}\text{x}-\frac{\sin(4\text{x}+10)}{8}+\text{C}$

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